A(5, 4), B(-3, -2) and C(1, -8) are the vertices of a triangle ABC. Find :
(i) the slope of the altitude of AB,
(ii) the slope of the median AD and
(iii) the slope of the line parallel to AC.

Question

A(5, 4), B(-3, -2) and C(1, -8) are the vertices of a triangle ABC. Find : (i) the slope of the altitude of AB, (ii) the slope of the median AD and (iii) the slope of the line parallel to AC.

KnowledgeBoat · Accepted Answer

(i) By formula, Slope = We know that, Product of slope of perpendicular lines = -1. ∴ Slope of AB × Slope of altitude = -1 ⇒ x Slope of altitude = -1 ⇒ Slope of altitude = Hence, slope of the altitude of AB = . (ii) Since, AD is median. So, D is the mid-point of BC. D = Hence, slope of the median AD = . (iii) Since, slope of parallel lines are equal. Hence, slope of line parallel to AC = 3.

Mathematics

A(5, 4), B(-3, -2) and C(1, -8) are the vertices of a triangle ABC. Find :
(i) the slope of the altitude of AB,
(ii) the slope of the median AD and
(iii) the slope of the line parallel to AC.

Straight Line Eq

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Mathematics

A(5, 4), B(-3, -2) and C(1, -8) are the vertices of a triangle ABC. Find :(i) the slope of the altitude of AB,(ii) the slope of the median AD and(iii) the slope of the line parallel to AC.

Straight Line Eq

Related Questions

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A(5, 4), B(-3, -2) and C(1, -8) are the vertices of a triangle ABC. Find :
(i) the slope of the altitude of AB,
(ii) the slope of the median AD and
(iii) the slope of the line parallel to AC.