Mathematics
AB = 4.5 cm, ∠B = 120° and the distance between AB and DC = 3.0 cm.
Rectilinear Figures
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Answer
Steps of construction :
Draw a line segment AB = 4.5 cm.
At B, draw BP ⊥ AB.
From BP, cut BE = 3 cm.
Through E draw a perpendicular to BP to get QR parallel to AB.
Draw BY, such that ∠B = 120°.
Let BY intersect QR at C.
With A as center and radius = BC, draw an arc cutting QR at D.
Join AD, BC and CD.

Hence, ABCD is the required parallelogram.
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