ab and ba are two 2-digit numbers then ab + ba is equal to :
2ab
11ab
11(a + b)
none of these
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ab + ba
= (10 x a + b) + (10 x b + a)
= 10a + b + 10b + a
= (10a + a) + (b + 10b)
= 11a + 11b
= 11(a + b)
Hence, option 3 is the correct option.
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For what value of digit x is :
3x2 divisible by 11 ?
5x2 a multiple of 11 ?
In a 2-digit number ab and a > b then ab - ba is equal to :
0
9(a - b)
9(b - a)
If a = b, then ab ÷ ba is equal to :