Mathematics
In △ABC, AB = AC and D is a point in side BC such that AD bisects angle BAC.
Show that AD is perpendicular bisector of side BC.
Related Questions
In △PQR; PQ = PR. A is a point in PQ and B is a point in PR, so that QR = RA = AB = BP.
(i) Show that: ∠P : ∠R = 1 : 3
(ii) Find the value of ∠Q.
The given figure shows a right triangle right angled at B.
If ∠BCA = 2∠BAC, show that AC = 2BC.
In the given figure, BC = CE and ∠1 = ∠2.
Prove that : △GCB ≡ △DCE.
The given figure shows two isosceles triangles ABC and DBC with common base BC. AD is extended to intersect BC at point P. Show that :
(i) △ABD ≡ △ACD.
(ii) △ABP ≡ △ACP.
(iii) AP bisects ∠BDC.
(iv) AP is perpendicular bisector of BC.
