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Mathematics

If ΔABC ∼ ΔQRP, ar(ΔABC)ar(ΔPQR)=94\dfrac{\text{ar(ΔABC)}}{\text{ar(ΔPQR)}} = \dfrac{9}{4}, AB = 18 cm and BC = 15 cm, then PR = ?

  1. 203\dfrac{20}{3} cm

  2. 8 cm

  3. 10 cm

  4. 12 cm

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Answer

Given,

AB = 18 cm

BC = 15 cm

Since the triangles are similar, the ratios of Areas of triangles is equal to the ratio of the squares of corresponding sides.

ar(ΔABC)ar(ΔPQR)=(BCPR)294=(15PR)294=15PR32=15PRPR=15×23PR=303PR=10 cm.\Rightarrow \dfrac{\text{ar(ΔABC)}}{\text{ar(ΔPQR)}} = \Big(\dfrac{BC}{PR}\Big)^2 \\[1em] \Rightarrow \dfrac{9}{4} = \Big(\dfrac{15}{PR}\Big)^2 \\[1em] \Rightarrow \sqrt{\dfrac{9}{4}} = \dfrac{15}{PR} \\[1em] \Rightarrow \dfrac{3}{2} = \dfrac{15}{PR} \\[1em] \Rightarrow PR = \dfrac{15 \times 2}{3} \\[1em] \Rightarrow PR = \dfrac{30}{3} \\[1em] \Rightarrow PR = 10 \text{ cm.}

Hence, option 3 is the correct option.

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