Mathematics
ABCD is a rectangle. X and Y are points on sides AD and BC respectively such that AX = BY, then :
AY ≠ BX
△ ABX ≅ △ BYA
△ ABX ≅ △ AYB
△ ABX ≅ △ BAY
Related Questions
From the adjoining figure, we find :
OP = OR
OP = OQ
PQ = PR
PR ≠ PQ

From the given figure, if ∠A = ∠C, we get :
x = 8, y = 16
x = -8, y = 16
x = 16, y = -8
x = 16, y = 8

In the given figure, P is mid-point of side AD of rectangle ABCD; then :
∠PBC = ∠PBA
∠PBC = ∠PCB
∠BPA = ∠BPC
∠PBC = ∠BPA

In the given figure, AB = AC. Prove that :
(i) DP = DQ
(ii) AP = AQ
(iii) AD bisects angle A

