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ABCD is a quadrilateral. If AL ⊥ BD and CM ⊥ BD, prove that : ar (quad.ABCD) = 12\dfrac{1}{2} × BD × (AL + CM).

ABCD is a quadrilateral. If AL ⊥ BD and CM ⊥  BD, prove that : ar (quad.ABCD). Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Theorems on Area

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Answer

We know that,

Area of triangle = 12\dfrac{1}{2} × Base × Height

Area of triangle ABD = 12\dfrac{1}{2} × BD × AL

Area of triangle CBD = 12\dfrac{1}{2} × BD × CM

We know that,

Area of quadrilateral ABCD = Area of △ ABD + Area of △ CBD

= 12\dfrac{1}{2} × BD × AL + 12\dfrac{1}{2} × BD × CM

= 12\dfrac{1}{2} × BD × (AL + CM).

Hence, proved that ar (quad. ABCD) = 12\dfrac{1}{2} × BD × (AL + CM).

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