Mathematics
ABCD is a rectangle and ABQC is a parallelogram. If the area of ΔABD is 5 sq. cm, then the area of the parallelogram is :
5 sq. cm
10 sq. cm
20 sq. cm
30 sq. cm
Theorems on Area
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Answer
In a rectangle, a diagonal divides it into two equal triangles.
So,
Area of rectangle ABCD = 2 × Area of △ABD
= 2 × 5
= 10 cm2.
Rectangle ABCD and parallelogram ABQC are on the same base AB and between the same parallel lines AB and DQ.
Area of the parallelogram ABQC = Area of rectangle ABCD = 10 cm2.
Hence, option 2 is the correct option.
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