Factorise : ab^2 - (a - c) b - c

ab 2 \- (a \- c) b \- c = ab 2 \- ab \+ bc \- c = ab(b \- 1) \+ c(b \- 1) = (b \- 1)(ab \+ c) Hence,ab 2 \- (a \- c) b \- c = (b \- 1)(ab \+ c)

Mathematics

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ab² - (a - c) b - c

= ab² - ab + bc - c

= ab(b - 1) + c(b - 1)

= (b - 1)(ab + c)

Hence,ab² - (a - c) b - c = (b - 1)(ab + c)

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