Add octal numbers (1546)₈ and (641)₈

$\begin{matrix} & \overset{1}{1} & \overset{1}{5} & 4 & 6 \ + & & 6 & 4 & 1 \ \hline & \bold{2} & \bold{4} & \bold{0} & \bold{7} \end{matrix}$

Therefore, (1546)₈ + (641)₈ = (2407)₈

Explanation

1. 6 + 1 = 7.
2. 4 + 4 = 8, as sum is equal to 8 so we will do 8 - 8 = 0. Hence, sum = 0, carry over = 1.
3. 1 + 5 + 6 = 12, as sum is greater than 8 so we will do 12 - 8 = 4. Hence, sum = 4, carry over = 1.
4. 1 + 1 = 2.