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The adjoining diagram shows two cross paths drawn inside a rectangular field 45 m long and 38 m wide, one parallel to length and the other parallel to breadth. The width of each path is 4 m. Find the cost of gravelling the paths at ₹ 5.60 per m2.

The adjoining diagram shows two cross paths drawn inside a rectangular field 45 m long and 38 m wide, one parallel to length and the other parallel to breadth. The width of each path is 4 m. Find the cost of gravelling the paths at ₹ 5.60 per m. ARC Properties of Circle, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

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Answer

Given,

Length of the field = 45 m

Width of the field = 38 m

Width of the each path = 4 m

Cost of gravelling = ₹ 5.60 per m2.

Area of path parallel to length:

⇒ Area = 45 × 4 = 180 m2.

Area of path parallel to breadth:

⇒ Area = 38 × 4 = 152 m2.

Since, both the path overlap in the middle :

⇒ So, the overlapped area = 4 × 4 = 16 m2.

⇒ Total area of paths = Area of first path + Area of second path - Overlapped area

= 180 + 152 - 16 = 316 m2.

⇒ Total cost = Area of paths × Cost per m2

= 316 × 5.60 = 1769.60

Hence, cost of gravelling the paths = ₹ 1,769.60

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