Mathematics
In the adjoining figure, in △ABC, AD is the median through A and E is the mid-point of AD. If BE produced meets AC in F, prove that AF = AC.
Related Questions
In the adjoining figure, ABCD is a kite in which AB = AD and CB = CD. If E, F, G are respectively the mid-points of AB, AD and CD, prove that :
(i) ∠EFG = 90°
(ii) If GH || FE, then H bisects CB.
In the adjoining figure, △ABC is right-angled at B and P is the mid-point of AC. Show that, PA = PB = PC.
Show that the quadrilateral formed by joining the mid-points of the pairs of adjacent sides of a rectangle is a rhombus.
