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Mathematics

In the adjoining figure, D is the mid-point of BC. Then the value of (cotycotx)\Big(\dfrac{\cot y}{\cot x}\Big) is:

  1. (12)\Big(\dfrac{1}{2}\Big)

  2. (13)\Big(\dfrac{1}{3}\Big)

  3. (14)\Big(\dfrac{1}{4}\Big)

  4. 2

The maximum volume of a cone that can be carved out of a solid hemisphere of radius r. Tangent Properties of Circles, RSA Mathematics Solutions ICSE Class 10.

Trigonometric Identities

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Answer

We know that,

cotθ=baseperpendicularcotycotx=ACBCACCDcotycotx=CDBCcotycotx=CD2CDcotycotx=12.cot θ = \dfrac{\text{base}}{\text{perpendicular}} \\[1em] \Rightarrow \dfrac{\cot y}{\cot x} = \dfrac{\dfrac{AC}{BC}}{\dfrac{AC}{CD}} \\[1em] \Rightarrow \dfrac{\cot y}{\cot x} = \dfrac{CD}{BC} \\[1em] \Rightarrow \dfrac{\cot y}{\cot x} = \dfrac{CD}{2CD} \\[1em] \Rightarrow \dfrac{\cot y}{\cot x} = \dfrac{1}{2} .

Hence, option 1 is the correct option.

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