Chemistry
Amit found that 30g of a gas occupied 1000 c.c at STP.
(a) What will the gram molecular weight and the vapour density of this gas be?
(b) How many molecules of this gas will be present in 44.8 l of it?
Stoichiometry
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Answer
Given,
Mass of gas = 30g
Volume = 1000 c.c = 1dm3 = 1 liter
We know one mole of gas at STP occupies 22.4 l
1 litres of gas at S.T.P. has mass = 30 g
∴ 22.4 litre (molar volume) has mass
= x 22.4
= 672 g/mol
Vapour density =
=
= 336
(b) 22.4 litres of the gas contains 6.023 x 1023 molecules
So, 44.8 litres of the gas contain 2 x 6.023 x 1023
= 12.046 x 10 23 molecules
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