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Chemistry

Ammonia burns in oxygen as shown below.

4NH3 + 3O2 ⟶ 2N2 + 6H2O

If 240 cc of ammonia is burnt in 300 cc of oxygen, find out the composition of the resultant gaseous mixture at room temperature.

Ammonia

ICSE 2024

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Answer

According to the given equation:

For N2

4 vol. of NH3 produce 2 vol. of N2

∴ 240 cc of NH3 will produce = 2×2404\dfrac{2 \times 240}{4} = 120 cc of N2

For O2

4 vol. of NH3 reacts with 3 vol. of O2

∴ 240 cc of NH3 will react with = 3×2404\dfrac{3 \times 240}{4} = 180 cc of O2.

Amount of unused Oxygen = 300 cc - 180 cc = 120 cc

Hence, composition of the resultant gaseous mixture at room temperature is 120 cc of O2 + 120 cc of N2

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