Mathematics

An A.P. consists of 60 terms. If the first and the last term be 7 and 125 respectively, find the 31st term.

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Answer

Given,

First term = a = 7,

Last term = a60 = a + (60 - 1)d

⇒ 125 = 7 + (59)d

⇒ 125 - 7 = 59d

⇒ 59d = 118

⇒ d = 2.

a31 = a + (31 - 1)d

= 7 + 30(2)

= 7 + 60

= 67.

Hence, 31st term = 67.

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