Mathematics

The angle of elevation of a tower from a distance of 100 m from its foot is 30°. The height of the tower is:
$\Big(\dfrac{100}{\sqrt{3}}\Big)$ m
$50\sqrt{3}$ m
$100\sqrt{3}$ m
$\Big(\dfrac{200}{\sqrt{3}}\Big)$ m

Heights & Distances

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Answer

The angle of elevation of a tower from a distance of 100 m from its foot is 30°. The height of the tower is: Volume And Surface Area of solid RSA Mathematics Solutions ICSE Class 10.

Let the height of tower (AB) be h meters.

Angle of elevation = 30°

$\Rightarrow \tan \theta = \dfrac{\text{perpendicular}}{\text{base}} \\[1em] \Rightarrow \tan 30^{\circ} = \dfrac{h}{100} \\[1em] \Rightarrow \dfrac{1}{\sqrt3} = \dfrac{h}{100} \\[1em] \Rightarrow h = \dfrac{100}{\sqrt3} \text{ m}.$

Hence, option 1 is the correct option.

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Mathematics

The angle of elevation of a tower from a distance of 100 m from its foot is 30°. The height of the tower is:
$\Big(\dfrac{100}{\sqrt{3}}\Big)$ m
$50\sqrt{3}$ m
$100\sqrt{3}$ m
$\Big(\dfrac{200}{\sqrt{3}}\Big)$ m

Heights & Distances

Answer

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$50\sqrt{3}$ m
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$\Big(\dfrac{200}{\sqrt{3}}\Big)$ m

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