The angles of elevation of an aeroplane flying vertically above the ground as observed from two consecutive stones 1 km apart are 45° and 60°. The height of the aeroplane above the ground (in km) is: 1. 2. 3. 4.

Question

KnowledgeBoat · Accepted Answer

Let the position of the aeroplane be A. Let h be the height of the aeroplane above the ground. Let C and D be the positions of the two consecutive stones on the ground. Let the distance from the closer stone C to the foot of the perpendicular B be x. Then, CD = x + 1. In △ABC, In △ABD, Substituting value of x from equation (2) in (1), we get : Hence, option 2 is the correct option.

Mathematics

The angles of elevation of an aeroplane flying vertically above the ground as observed from two consecutive stones 1 km apart are 45° and 60°. The height of the aeroplane above the ground (in km) is: 1. 2. 3. 4.

Heights & Distances

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