In the given figure, squares ABDE and AFGC are drawn on the side AB and hypotenuse AC of right triangle ABC and BH ⟂ FG. Prove that :

(i) ∠EAC = ∠BAF

(ii) ar (sq. ABDE) = ar (rect. ARHF)

Construct a quadrilateral ABCD in which AB = 3.2 cm, BC = 2.8 cm, CD = 4 cm, DA = 4.5 cm and BD = 5.3 cm. Also construct a triangle equal in area to this quadrilateral.

The area of the trapezium whose parallel sides are 9 cm and 6 cm respectively and distance between these sides is 8 cm, will be :

1. 50 cm²

2. 60 cm²

3. 70 cm²

4. 80 cm²

Area of parallelogram ABCD in the figure will be :

1. 15 cm²

2. 25 cm²

3. 35 cm²

4. 45 cm²