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Mathematics

In an army camp, 300 soldiers had provisions for 13 days. If 40 of them are transferred to the other camp, how long will the provisions last?

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Answer

Original soldiers = 300.

Remaining soldiers = 300 - 40 = 260.

Provisions for 300 soldiers last = 13 days.

Provisions for 1 soldier last = (13 x 300) days. \quad [Less soldiers, More days]

Provisions for 260 soldiers last = (13×300260) days[More soldiers, Less days]\Big(\dfrac{13 \times 300}{260}\Big) \text{ days} \quad \text{[More soldiers, Less days]}

= (1×30020) days[Dividing 13 and 260 by 13]\Big(\dfrac{1 \times 300}{20}\Big) \text{ days} \quad \text{[Dividing 13 and 260 by 13]}

= 15 days.

260 soldiers had provisions for 15 days

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