Mathematics
Arrange the following decimal numbers in ascending order:
(i) 123.8, 74.205, 74.209, 7.4209
(ii) 85.01, 85.1, 85.001, 85.103
Answer
(i) The maximum number of decimal places in the given decimals is 4. So, we convert each of the given decimals into like decimals having four decimal places by annexing zeros.
The decimals are: 123.8000, 74.2050, 74.2090, 7.4209
Clearly, 7.4209 < 74.2050 < 74.2090 < 123.8000.
Hence, the given decimals in ascending order are:
7.4209 < 74.205 < 74.209 < 123.8
(ii) The maximum number of decimal places in the given decimals is 3. So, we convert each of the given decimals into like decimals having three decimal places by annexing zeros.
The decimals are: 85.010, 85.100, 85.001, 85.103
Clearly, 85.001 < 85.010 < 85.100 < 85.103.
Hence, the given decimals in ascending order are:
85.001 < 85.01 < 85.1 < 85.103
Related Questions
Convert the following decimal numbers into fractions (in lowest terms):
(i) 6.015
(ii) 0.876
(iii) 23.375
Arrange the following decimal numbers in descending order:
(i) 6.45, 4.65, 6.405, 64.5
(ii) 73.5, 35.7, 7.35, 7.035
If the school bags of Garima and Nakul weigh 5.2 kg and 4.832 kg respectively, find
(i) the total weight
(ii) the difference in weight of the bags