Arrange the given fractions in ascending order:

(i) $\dfrac{7}{8}, \dfrac{15}{16}, \dfrac{5}{6}$

(ii) $\dfrac{3}{4}, \dfrac{15}{22}, \dfrac{26}{33}$

(iii) $\dfrac{5}{12}, \dfrac{1}{4}, \dfrac{7}{8}, \dfrac{5}{6}$

(i) $\dfrac{7}{8}, \dfrac{15}{16}, \dfrac{5}{6}$

LCM of 8, 16 and 6 = 48.

Write the given fractions as equivalent like fractions.

$\Rightarrow \dfrac{7}{8} = \dfrac{7 \times 6}{8 \times 6} = \dfrac{42}{48} \\[1em] \Rightarrow \dfrac{15}{16} = \dfrac{15 \times 3}{16 \times 3} = \dfrac{45}{48} \\[1em] \Rightarrow \dfrac{5}{6} = \dfrac{5 \times 8}{6 \times 8} = \dfrac{40}{48}$

As 40 < 42 < 45,

$\dfrac{40}{48} \lt \dfrac{42}{48} \lt \dfrac{45}{48} \Rightarrow \dfrac{5}{6} \lt \dfrac{7}{8} \lt \dfrac{15}{16}$.

Hence, the given fractions in ascending order are $\dfrac{5}{6}, \dfrac{7}{8}, \dfrac{15}{16}$.

(ii) $\dfrac{3}{4}, \dfrac{15}{22}, \dfrac{26}{33}$

LCM of 4, 22 and 33 = 132.

Write the given fractions as equivalent like fractions.

$\Rightarrow \dfrac{3}{4} = \dfrac{3 \times 33}{4 \times 33} = \dfrac{99}{132} \\[1em] \Rightarrow \dfrac{15}{22} = \dfrac{15 \times 6}{22 \times 6} = \dfrac{90}{132} \\[1em] \Rightarrow \dfrac{26}{33} = \dfrac{26 \times 4}{33 \times 4} = \dfrac{104}{132}$

As 90 < 99 < 104,

$\dfrac{90}{132} \lt \dfrac{99}{132} \lt \dfrac{104}{132} \Rightarrow \dfrac{15}{22} \lt \dfrac{3}{4} \lt \dfrac{26}{33}$.

Hence, the given fractions in ascending order are $\dfrac{15}{22}, \dfrac{3}{4}, \dfrac{26}{33}$.

(iii) $\dfrac{5}{12}, \dfrac{1}{4}, \dfrac{7}{8}, \dfrac{5}{6}$

LCM of 12, 4, 8 and 6 = 24.

Write the given fractions as equivalent like fractions.

$\Rightarrow \dfrac{5}{12} = \dfrac{5 \times 2}{12 \times 2} = \dfrac{10}{24} \\[1em] \Rightarrow \dfrac{1}{4} = \dfrac{1 \times 6}{4 \times 6} = \dfrac{6}{24} \\[1em] \Rightarrow \dfrac{7}{8} = \dfrac{7 \times 3}{8 \times 3} = \dfrac{21}{24} \\[1em] \Rightarrow \dfrac{5}{6} = \dfrac{5 \times 4}{6 \times 4} = \dfrac{20}{24}$

As 6 < 10 < 20 < 21,

$\dfrac{6}{24} \lt \dfrac{10}{24} \lt \dfrac{20}{24} \lt \dfrac{21}{24} \Rightarrow \dfrac{1}{4} \lt \dfrac{5}{12} \lt \dfrac{5}{6} \lt \dfrac{7}{8}$.

Hence, the given fractions in ascending order are $\dfrac{1}{4}, \dfrac{5}{12}, \dfrac{5}{6}, \dfrac{7}{8}$.