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Mathematics

Ashok lent out ₹ 7,000 at 6% and ₹ 9,500 at 5%. Find his total income from the interest in 3 years.

Simple Interest

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Answer

Given:

P = ₹ 7,000

R = 6%

T = 3 years

S.I.=(P×R×T100)S.I.=(7,000×6×3100)S.I.=1,26,000100S.I.=1,260\because \text{S.I.} = ₹ \Big(\dfrac{P \times R \times T}{100}\Big)\\[1em] \Rightarrow \text{S.I.} = ₹ \Big(\dfrac{7,000 \times 6 \times 3}{100}\Big)\\[1em] \Rightarrow \text{S.I.} = ₹ \dfrac{1,26,000}{100}\\[1em] \Rightarrow \text{S.I.} = ₹ 1,260

P = ₹ 9,500

R = 5%

T = 3 years

S.I.=(P×R×T100)S.I.=(9,500×5×3100)S.I.=1,42,500100S.I.=1,425\because \text{S.I.} = ₹ \Big(\dfrac{P \times R \times T}{100}\Big)\\[1em] \Rightarrow \text{S.I.} = ₹ \Big(\dfrac{9,500 \times 5 \times 3}{100}\Big)\\[1em] \Rightarrow \text{S.I.} = ₹ \dfrac{1,42,500}{100}\\[1em] \Rightarrow \text{S.I.} = ₹ 1,425

Total income from the interest = ₹ 1,260 + ₹ 1,425 = ₹ 2,685

Hence, total amount from the interest in 3 years = ₹ 2,685.

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