Statement 1: $\Big(\dfrac{5}{8}\Big)^{-7} \times \Big(\dfrac{8}{5}\Big)^{-4} = x$

⇒ x = $\Big(\dfrac{5}{8}\Big)^{3}$

Statement 2: $\Big(\dfrac{5}{8}\Big)^{-7} \times \Big(\dfrac{5}{8}\Big)^{4} = x$

⇒ x = $\Big(\dfrac{8}{5}\Big)^{3}$

1. Both the statements are true.

2. Both the statements are false.

3. Statement 1 is true, and statement 2 is false.

4. Statement 1 is false, and statement 2 is true.

Assertion (A): (3^-7 ÷ 3^-10) x 3^-5 = $\dfrac{1}{9}$.

Reason (R): $\dfrac{1}{3^7} \times 3^{10} \times \dfrac{1}{3^5}$.

1. A is true, but R is false.

2. A is false, but R is true.

3. Both A and R are true, and R is the correct reason for A.

4. Both A and R are true, and R is the incorrect reason for A.

Evaluate :

$9^{\dfrac{5}{2}} - 3 \times 8^0 - \Big(\dfrac{1}{81}\Big)^{-\dfrac{1}{2}}$

Evaluate :

$(64)^{\dfrac{2}{3}} - \sqrt[3]{125} - \dfrac{1}{2^{-5}} + (27)^{-\dfrac{2}{3}} \times \Big(\dfrac{25}{9}\Big)^{-\dfrac{1}{2}}$