Mathematics
Assertion (A) : For constructing frequency polygon, class-marks should be calculated.
Reason (R) : To construct a frequency polygon, we take class marks along x-axis and corresponding frequencies along y-axis.
A is true, R is the false
A is false, R is true
Both A and R are true
Both A and R are false.
Statistics
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Answer
A frequency polygon is drawn by plotting frequencies against class marks (mid-points) of class intervals.
∴ Assertion (A) is true.
To construct a frequency polygon, we mark points taking values of class-marks along x-axis and the values of their corresponding frequencies along y-axis.
∴ Reason (R) is true.
Hence option 3 is the correct option.
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Related Questions
If the lower limit of a class-interval is 48 and the class-mark is 55, then the upper limit is :
60
62
64
61
If the class-intervals in a frequency distribution are 1 - 11, 11 - 21, 21 - 31, etc., then class 1 - 11 means :
more than 1 and less than 11
1 or more but less than 11
equal to or more than 1 but equal to or less than 11
more than 1 but less than or equal to 11
Directions:
Study the following table carefully and answer the questions that follow:
Age (in years) Number of employees (Frequency) Cumulative frequency 30 - 35 5 5 35 - 40 7 12 40 - 45 6 18 45 - 50 9 27 50 - 55 4 31 Based on above table, answer the following questions:
- The total number of employees is :
(a) 30
(b) 31
(c) 55
(d) Cannot be determined- How many employees are less than 50 years of age?
(a) 9
(b) 18
(c) 27
(d) 31- How many employees are atleast 40 years old?
(a) 12
(b) 18
(c) 19
(d) 27- What is the difference between the class-mark of the first and last class intervals?
(a) 20
(b) 22.5
(c) 25
(d) 27.5Assertion (A) : If the class-mark of a class is 9.5 and the class size is 6, then the class interval is 6 - 12.
Reason (R) : Class mark =
A is true, R is the false
A is false, R is true
Both A and R are true
Both A and R are false.