Assertion (A): A die is thrown twice. The probability of getting a bigger value on the first throw is . Reason (R): When we throw a die once, total number of possible outcomes is 6 and when the die is thrown twice, the total number of possible outcomes is 6 + 6 = 12. 1. A is true, R is false 2. A is false, R is true 3. Both A and R are true 4. Both A and R are false

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KnowledgeBoat · Accepted Answer

When a dice is thrown twice, Total number of outcomes = 36 Let E be the event of getting a bigger value on the first throw, E = {(2, 1), (3, 1), (3, 2), (4, 1), (4, 2), (4, 3), (5, 1), (5, 2), (5, 3), (5, 4), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5)} The number of favorable outcomes of the event E = 15 Therefore, Assertion (A) is true When a single die is thrown, there are 6 possible outcomes {1, 2, 3, 4, 5, 6}. When a die is thrown twice, the total number of outcomes is determined by the product of the outcomes of each throw: Total Outcomes = 6 × 6 = 36 Reason (R) is false. A is true, R is false Hence, option 1 is the correct option.

Mathematics

Probability

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