Assertion (A): For the equation 4y - 7x + 28 = 0, the value of a is -8. x -7 8 y a 7 Reason (R): 4y - 7x + 28 = 0 ⇒ 4y + 49 + 28 = 0 ⇒ y = -77/4 i.e. a = -(77/4) 1. A is true, R is false. 2. A is false, R is true. 3. Both A and R are true. 4. Both A and R are false.

A is false, R is true. Explanation Given, 4y - 7x + 28 = 0 When x = -7 and y = a, 4 x a - 7 x (-7) + 28 = 0 ⇒ 4a + 49 + 28 = 0 ⇒ 4a + 77 = 0 ⇒ 4a = - 77 ⇒ a = - According to Assertion, the value of a = -8 (≠ - ) ∴ Assertion (A) is false. From the above calculation, a = ∴ Reason (R) is true. Hence, Assertion (A) is false, Reason (R) is true.

Mathematics

Assertion (A): For the equation 4y - 7x + 28 = 0, the value of a is -8.
x -7 8
y a 7
Reason (R):
4y - 7x + 28 = 0
⇒ 4y + 49 + 28 = 0
⇒ y = $\dfrac{-77}{4}$ i.e. a = $-\dfrac{77}{4}$
A is true, R is false.
A is false, R is true.
Both A and R are true.
Both A and R are false.

Graphical Solution

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Answer

A is false, R is true.

Explanation

Given,

4y - 7x + 28 = 0

When x = -7 and y = a,

4 x a - 7 x (-7) + 28 = 0

⇒ 4a + 49 + 28 = 0

⇒ 4a + 77 = 0

⇒ 4a = - 77

⇒ a = - $\dfrac{77}{4}$

According to Assertion, the value of a = -8 (≠ - $\dfrac{77}{4}$ )

∴ Assertion (A) is false.

From the above calculation, a = $-\dfrac{77}{4}$

∴ Reason (R) is true.

Hence, Assertion (A) is false, Reason (R) is true.

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Mathematics

Assertion (A): For the equation 4y - 7x + 28 = 0, the value of a is -8.
x -7 8
y a 7
Reason (R):
4y - 7x + 28 = 0
⇒ 4y + 49 + 28 = 0
⇒ y = $\dfrac{-77}{4}$ i.e. a = $-\dfrac{77}{4}$
A is true, R is false.
A is false, R is true.
Both A and R are true.
Both A and R are false.

Graphical Solution

Answer

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Mathematics

Assertion (A): For the equation 4y - 7x + 28 = 0, the value of a is -8.x-78ya7Reason (R):4y - 7x + 28 = 0⇒ 4y + 49 + 28 = 0⇒ y = −774\dfrac{-77}{4}4−77​ i.e. a = −774-\dfrac{77}{4}−477​A is true, R is false.A is false, R is true.Both A and R are true.Both A and R are false.

Graphical Solution

Answer

Related Questions

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Assertion (A): The graph of 2x = 1 is a line parallel to y-axis.Reason (R): The equations of the form x = ± k are always parallel to y-axis.A is true, R is false.A is false, R is true.Both A and R are true.Both A and R are false.

Assertion (A): If A = (2x, y), B = (x, 2y) and AB = 5 unit, then x + y = 5.Reason (R):AB = 5 ⇒ (2x−x)2+(y−2y)2\sqrt{(2x - x)^2 + (y - 2y)^2}(2x−x)2+(y−2y)2​ = 5⇒ x2 - y2 = 25A is true, R is false.A is false, R is true.Both A and R are true.Both A and R are false.

Assertion (A): For the equation 4y - 7x + 28 = 0, the value of a is -8.
x -7 8
y a 7
Reason (R):
4y - 7x + 28 = 0
⇒ 4y + 49 + 28 = 0
⇒ y = $\dfrac{-77}{4}$ i.e. a = $-\dfrac{77}{4}$
A is true, R is false.
A is false, R is true.
Both A and R are true.
Both A and R are false.

Assertion (A): The graph of 2x = 1 is a line parallel to y-axis.
Reason (R): The equations of the form x = ± k are always parallel to y-axis.
A is true, R is false.
A is false, R is true.
Both A and R are true.
Both A and R are false.

Assertion (A): If A = (2x, y), B = (x, 2y) and AB = 5 unit, then x + y = 5.
Reason (R):
AB = 5 ⇒ $\sqrt{(2x - x)^2 + (y - 2y)^2}$ = 5
⇒ x² - y² = 25
A is true, R is false.
A is false, R is true.
Both A and R are true.
Both A and R are false.