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Mathematics

Assertion (A) : In the figure, ABCD is a parallelogram. Area of ΔABD = 12\dfrac{1}{2} Area of ∥ gm ABCD.

Reason (R) : If a triangle and a parallelogram are on the same base and between the same parallels, then area of the triangle is equal to half of the area of the parallelogram.

If a triangle and a parallelogram are on the same base and between the same parallels, then area of the triangle is equal to half of the area of the parallelogram. Quadrilaterals, R.S. Aggarwal Mathematics Solutions ICSE Class 9.
  1. A is true, R is false

  2. A is false, R is true

  3. Both A and R are true

  4. Both A and R are false

Theorems on Area

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Answer

In a parallelogram ABCD, the diagonal BD divides it into two triangles ΔABD and ΔBCD of equal area.

Area of △ABD = 12\dfrac{1}{2} × Area of parallelogram ABCD

Assertion (A) is true.

The statement is a standard area theorem:

If a triangle and a parallelogram are on the same base and between the same parallels, then the area of the triangle is half the area of the parallelogram.

Reason (R) is true.

Both A and R are true.

Hence, option 3 is the correct option.

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