Mathematics
Assertion (A) : In the figure, ABCD is a parallelogram. Area of ΔABD = Area of ∥ gm ABCD.
Reason (R) : If a triangle and a parallelogram are on the same base and between the same parallels, then area of the triangle is equal to half of the area of the parallelogram.

A is true, R is false
A is false, R is true
Both A and R are true
Both A and R are false
Theorems on Area
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Answer
In a parallelogram ABCD, the diagonal BD divides it into two triangles ΔABD and ΔBCD of equal area.
Area of △ABD = × Area of parallelogram ABCD
Assertion (A) is true.
The statement is a standard area theorem:
If a triangle and a parallelogram are on the same base and between the same parallels, then the area of the triangle is half the area of the parallelogram.
Reason (R) is true.
Both A and R are true.
Hence, option 3 is the correct option.
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Related Questions
E is the mid-point of the side AB of a parallelogram ABCD. If the area of the ABCD is 60 sq. cm, then the area of ΔBDE is :
60 sq. cm
30 sq. cm
15 sq. cm
10 sq. cm
Case Study :
A farmer was having a field in the form of a parallelogram ABCD. He divided the field into several parts by taking a point X on the side CD and joining it to vertices A and B. The farmer sowed wheat and pulses in equal portions of the field separately.
Based on the above information, answer the following questions :
1. By joining XA and XB, the field has been divided into how many parts?
(a) 2
(b) 3
(c) 4
(d) 52. The shapes of the parts obtained above are :
(a) triangles
(b) rectangles
(c) one triangle two squares
(d) none of these3. Area of ΔXAB is equal to :
(a) area of parallelogram ABCD
(b) area of parallelogram ABCD
(c) area of ΔADX + area of ΔBCX
(d) both 2. and 3.4. ΔABX and parallelogram ABCD are :
(a) On the same base DC
(b) On the same base AB and between the same parallels BC and AD
(c) On the same base AB and between the same parallels AB and CD
(d) On the same base CD and between the same parallels AB and CD5.If instead of taking point X on side CD, the farmer takes a point Y on side BC and joins YA and YD, then :
(a) area of ΔADY = area of ΔABY + area of ΔDCY
(b) area of ΔADY = area of parallelogram ABCD
(c) area of ΔADY = area of ΔABY
(d) area of ΔADY = area of ΔDCYAssertion (A) : In ΔABC, if D is the mid-point of side AB, then area of ΔBCD = area of ΔACD.
Reason (R) : A triangle and a parallelogram on the same base and between the same parallels are equal in area.

A is true, R is false
A is false, R is true
Both A and R are true
Both A and R are false
In which of the following, you find two polygons on the same base and between the same parallels?
- 1.

- 2.

- 3.

- 4.
