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Mathematics

Assertion (A): The mean proportion between a2b and 1b\dfrac{1}{b} is ab\dfrac{a}{b}.

Reason (R): The mean proportion between x and y is given by xy\sqrt{xy}.

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Ratio Proportion

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Answer

We know that,

Mean proportion between two numbers

= First number×Second number\sqrt{\text{First number} \times \text{Second number}}

Thus,

The mean proportion between x and y is given by xy\sqrt{xy}.

∴ Reason (R) is true.

Thus,

The mean proportion between a2b and 1b\dfrac{1}{b} = a2b×1b\sqrt{a^2b \times \dfrac{1}{b}}

=a2=a= \sqrt{a^2} = a.

∴ Assertion (A) is false.

Hence, option 4 is the correct option.

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