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Mathematics

Assertion (A): The nth term of a G.P. is given by Tn = arn − 1.

Reason (R): A sequence a1, a2, a3, ……. is said to be a G.P. if a2a1=a3a2=a4a3\dfrac{a2}{a1} = \dfrac{a3}{a2} = \dfrac{a4}{a3} = constant known as the common ratio.

  1. A is true, R is false.

  2. A is false, R is true.

  3. Both A and R are true.

  4. Both A and R are false.

G.P.

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Answer

The nth term of a G.P. is given by :

Tn = arn - 1

Assertion (A) is true.

A sequence a1,a2,a3,a1, a2, a3, \dots is said to be a G.P. if a1a2=a2a3=a3a4=constant\dfrac{a1}{a2} = \dfrac{a2}{a3} = \dfrac{a3}{a_4} = \text{constant} known as the common ratio.

A sequence is a G.P. if the ratio between any consecutive terms is a constant value. This constant is called the common ratio.

Reason is true.

Both A and R are true.

Hence, option 3 is the correct option.

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