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Mathematics

Assertion (A): If sec θ + tan θ = p, then sec θ = 2pp2+1\dfrac{2p}{p^2 + 1}

Reason (R): sec2 θ − tan2 θ = 1

  1. A is true, R is false

  2. A is false, R is true

  3. Both A and R are true

  4. Both A and R are false

Trigonometric Identities

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Answer

Given,

sec θ + tan θ = p

We know that,

sec2 θ − tan2 θ = 1

(sec θ + tan θ)(sec θ − tan θ) = 1

(p)(sec θ − tan θ) = 1

sec θ − tan θ = 1p\dfrac{1}{p}

Add sec θ + tan θ and sec θ − tan θ,

sec θ + tan θ + sec θ − tan θ = p + 1p\dfrac{1}{p}

2sec θ = p2+1p\dfrac{p^2 + 1}{p}

sec θ = p2+12p\dfrac{p^2 + 1}{2p}

Assertion (A) is false.

sec2 θ − tan2 θ = 1 is a standard Pythagorean Identity.

Reason is true.

A is false, R is true

Hence, option 2 is the correct option.

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