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Mathematics

Assertion (A) : The third quartile of the data 1, 20, 3, 15, 6, 8, 13, 5, 21, 23, 17, 10, 9, 12, 18, 21 is 18

Reason (R) : For an ungrouped data, containing n observations, the upper quartile is given by,

Q3 = 3n4+1\dfrac{\text{3n}}{4} + 1 th observation, if n is even.

  1. A is true, R is false

  2. A is false, R is true

  3. Both A and R are true

  4. Both A and R are false

Measures of Central Tendency

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Answer

Observations arranging in ascending order = 1, 3, 5, 6, 8, 9, 10, 12, 13, 15, 17, 18, 20, 21, 21, 23

Here, n = 16

We know that,

If the variates are arranged in ascending order, then the observation lying midway between the median and the upper extreme is called the Upper quartile or Third quartile.

Q3 = 3n4\dfrac{3\text{n}}{4} th observation, if n is even.

= 3×164=484\dfrac{3 \times 16}{4} = \dfrac{48}{4} = 12 th observation = 18.

∴ Assertion (A) is true.

For an ungrouped data, containing n observations, upper quartile is given by,

Q3 = 3n4\dfrac{3\text{n}}{4} th observation, if n is even.

∴ Reason (R) is false.

Hence, Option 1 is the correct option.

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