Mathematics
Assertion (A): Total surface area of semi-circle is 18.48 cm2. Its radius is 14 cm.
Reason (R): Total surface area of a semi-circle of radius r is given by 2πr2.
A is true, R is false
A is false, R is true
Both A and R are true
Both A and R are false
Mensuration
1 Like
Answer
Total surface area of semicircle formula =
Considering radius = 14 cm
Total surface area of semicircle = × 142
= 308 cm2.
But the given assertion says 18.48 cm2.
∴ Both Assertion and Reason are false.
Hence, option 4 is the correct option.
Answered By
3 Likes
Related Questions
Case Study
Mr Ranveer lives in Agra. He purchased a rectangular plot ABCD to build a house. He leaves a rectangular area ADEF for parking and two congruent semicircular areas to make lower beds, as shown in the figure.
Based on the above information, answer the following questions:
Area of the plot left for parking is:
(a) 24 m2
(b) 48 m2
(c) 60 m2
(d) 63 m2Diameter of each semi-circle is:
(a) 21 m
(b) 10.5 m
(c) 7 m
(d) 3.5 mTotal area of the two semi-circular flower beds is :
(a) 80.6 m2
(b) 82.625 m2
(c) 86.625 m2
(d) 90.625 m2Area of the plot BCEF is :
(a) 441 m2
(b) 400 m2
(c) 380 m2
(d) 350 m2Total length of the two semi-circular arcs is :
(a) 33 m
(b) 35 m
(c) 16.5 m
(d) 54 m
Case Study
Some mementos are ordered by a school for awarding their students on the occasion of Annual Day. Each memento is designed as shown in the figure, where its base ABCD is silver plated from the front side at the rate of ₹50 per cm2.
Based on the above information, answer the following questions:
Area of △AOB is :
(a) 50 cm2
(b) 52 cm2
(c) 56 cm2
(d) 60 cm2Length of the arc CD is :
(a) 44 cm
(b) 22 cm
(c) 15 cm
(d) 11 cmArea of quadrant OCDO is :
(a) 154 cm2
(b) 77 cm2
(c) 38.5 cm2
(d) 30.5 cm2Area of major sector formed in the figure is :
(a) 154 cm2
(b) 77 cm2
(c) 100.5 cm2
(d) 115.5 cm2Total cost of silver plating is :
(a) ₹575
(b) ₹500
(c) ₹450
(d) ₹400
Assertion (A): The diameter of a cycle wheel is 21 cm. It will make 2000 revolutions to cover a distance of 1.32 km.
Reason (R): Distance covered by a wheel of radius r in one revolution is given by 2πr.
A is true, R is false
A is false, R is true
Both A and R are true
Both A and R are false
The number of rounds that a wheel of diameter m will make in going 4 km is :
1600
1800
1900
2000