Mathematics
Assertion (A): Using the information in the given figure, we get : ∠PQR = ∠PSR = 90°

Reason (R):

By SSS, △PQR = △PSR
⇒ ∠PQR = ∠PSR
Since, ∠PQR + ∠PSR ≠ 180°
∴ ∠PQR = ∠PSR ≠ 90°
- A is true, R is false.
- A is false, R is true.
- Both A and R are true.
- Both A and R are false.
Triangles
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Answer
A is false, R is true.
Explanation
Given,
Join PR.

In △PQR and △PSR,
PR (Common side)
PQ = PS (Given)
QR = RS (Given)
∴ △PQR ≅ △PSR (By SSS)
By C.P.C.T.C.
∠PQR = ∠PSR
∠RPQ = ∠RPS
∠PRQ = ∠PRS
Assuming, ∠PQR = ∠PSR = 90°
⇒ ∠QPS = QRS = 90° [∵ Sum of interior ∠s of quadrilateral is 360°]
So, PQRS should be a rectangle with all it's angles equal to 90°.
But PQRS is not a rectangle as opposite sides are not equal.
PS ≠ QR and PQ ≠ SR
Hence our assumption ∠PQR = ∠PSR = 90° is incorrect.
∴ ∠PQR = ∠PSR ≠ 90°
∴ Assertion (A) is false.
∴ Reason (R) is true.
Hence, Assertion (A) is false, Reason (R) is true.
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