Assertion (A): (x^-1 - y^-1) × (x - y)^-1 = x^-1 × y^-1 Reason (R): For any non-zero number x, x^-1 = 1/3 1. A is true, R is false 2. A is false, R is true 3. Both A and R are true 4. Both A and R are false

Question

KnowledgeBoat · Accepted Answer

Given, (x-1 - y-1) × (x - y)-1 = x-1y-1 Solving L.H.S, L.H.S R.H.S Thus, Assertion (A) is false. For any non-zero number x, the notation x−1 is defined as its multiplicative inverse, which is equal to Thus, Reason (R) is true. A is false, R is true Hence, option 2 is the correct option.

Mathematics

Assertion (A): (x^-1 - y^-1) × (x - y)^-1 = x^-1 × y^-1 Reason (R): For any non-zero number x, x^-1 = 1/3 1. A is true, R is false 2. A is false, R is true 3. Both A and R are true 4. Both A and R are false

Indices

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(x^a)^{(b - c)} (x^b)^{(c - a)}(x^c)^{(a - b)} =
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Mathematics

Assertion (A): (x^-1 - y^-1) × (x - y)^-1 = x^-1 × y^-1 Reason (R): For any non-zero number x, x^-1 = 1/3 1. A is true, R is false 2. A is false, R is true 3. Both A and R are true 4. Both A and R are false

Indices

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(xa)(b - c) (xb)(c - a)(xc)(a - b) =0123

(x^a)^{(b - c)} (x^b)^{(c - a)}(x^c)^{(a - b)} =
0
1
2
3