Case Study III
Tanusha went to a bank to withdraw money. She asked the cashier to give her ₹ 100 and ₹ 500 rupee notes only. The cashier agreed. Tanusha got x, ₹ 100-rupee notes and y, 500-rupee notes.

Based on this information, answer the following questions.

1. If Tanusha withdrew ₹ 15,000, then the above information can be represented by the linear equation:
   (a) x + 5y = 150
   (b) 5x + y = 150
   (c) x + 5y + 150 = 0
   (d) x + y = 150

2. If she got 54 notes in all, then the above information can be represented by the linear equation:
   (a) 100x + 500y = 54
   (b) x + y = 54
   (c) 500x + 100y = 54
   (d) 100x + y = 54

3. If Tanusha withdraws ₹16 000, then which combination of notes might she get?
   (a) ₹500 notes = 30, ₹100 notes = 20
   (b) ₹500 notes = 25, ₹100 notes = 25
   (c) ₹500 notes = 20, ₹100 notes = 30
   (d) ₹500 notes = 30, ₹100 notes = 10

4. If she gets twenty 500-rupee notes and twenty-five 100-rupee notes, then the amount she withdraws is:
   (a) ₹10,000
   (b) ₹11,000
   (c) ₹12,000
   (d) ₹12,500

5. Can Tanusha withdraw ₹10,050 under the given conditions?
   (a) yes
   (b) no
   (c) can’t say anything
   (d) none of these

Assertion(A): If 8x + 7y = 37 and 7x + 8y = 38, then x = -2, y = 3.

Reason(R): ax + by = c and bx + ay = d is not simultaneous linear equations in two variables.

1. A is true, R is false

2. A is false, R is true

3. Both A and R are true

4. Both A and R are false

Assertion(A): A pair of linear equations in two variables cannot have more than one solution.

Reason(R): If we solve a pair of linear equations in two variables, first by elimination method and then by cross multiplication method, then in some cases the two solutions so obtained may be different.

1. A is true, R is false

2. A is false, R is true

3. Both A and R are true

4. Both A and R are false

If 0.4x + 0.3y = 2.3 and 2.5x - 2y = -5, then the value of xy is :

1. 10

2. 12

3. 2.4

4. 1.2