Factorise : a^2 + 2ab + b^2 - c^2

a 2 \+ 2ab \+ b 2 \- c 2 Using the formula [∵ (x \+ y) 2 = x 2 \+ y 2 \+ 2xy] = (a 2 \+ 2ab \+ b 2 ) \- c 2 = ((a) 2 \+ 2 a b \+ (b) 2 ) \- c 2 = (a \+ b) 2 \- (c) 2 Using the formula [∵ (x 2 \- y 2 ) = (x \+ y)(x \- y)] = ((a \+ b) \+ c)((a \+ b) \- c) = (a \+ b \+ c)(a \+ b \- c) Hence,a 2 \+ 2ab \+ b 2 \- c 2 = (a \+ b \+ c)(a \+ b \- c)

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Mathematics

Factorise :
a² + 2ab + b² - c²

Factorisation

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Mathematics

Factorise :
a² + 2ab + b² - c²

Factorisation

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Mathematics

Factorise :a2 + 2ab + b2 - c2

Factorisation

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Factorise :
a² + 2ab + b² - c²

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Factorise :
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Factorise :
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