a 2 - b 2 - (a + b) 2

Given, a 2 - b 2 - (a + b) 2 = (a + b)(a - b) - (a + b) 2 = (a + b)[(a - b) - (a + b)] = (a + b)[a - b - a - b] = -2b(a + b). Hence, a 2 - b 2 - (a + b) 2 = -2b(a + b).

Mathematics

Factorise :
a² - b² - (a + b)²

Factorisation

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Answer

Given,

a² - b² - (a + b)²

= (a + b)(a - b) - (a + b)²

= (a + b)[(a - b) - (a + b)]

= (a + b)[a - b - a - b]

= -2b(a + b).

Hence, a² - b² - (a + b)² = -2b(a + b).

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Mathematics

Factorise :
a² - b² - (a + b)²

Factorisation

Answer

Related Questions

Factorise :
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27 + 8x³ in the form of factors is :
(3 + 2x)(9 + 6x + 4x²)
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Mathematics

Factorise :a2 - b2 - (a + b)2

Factorisation

Answer

Related Questions

Factorise :(x2 + 4y2 - 9z2)2 - 16x2y2

Factorise :(a + b)2 - a2 + b2

a3 - 8 in the form of factors is :(a - 2)(a2 - 2a + 4)(a - 2)(a2 + 2a + 4)(a - 2)(a2 + 2a - 4)(a + 2)(a2 - 2a + 4)

27 + 8x3 in the form of factors is :(3 + 2x)(9 + 6x + 4x2)(3 - 2x)(9 + 6x + 4x2)(3 + 2x)(9 - 6x + 4x2)(3 - 2x)(9 - 6x + 4x2)

Factorise :
a² - b² - (a + b)²

Factorise :
(x² + 4y² - 9z²)² - 16x²y²

Factorise :
(a + b)² - a² + b²

a³ - 8 in the form of factors is :
(a - 2)(a² - 2a + 4)
(a - 2)(a² + 2a + 4)
(a - 2)(a² + 2a - 4)
(a + 2)(a² - 2a + 4)

27 + 8x³ in the form of factors is :
(3 + 2x)(9 + 6x + 4x²)
(3 - 2x)(9 + 6x + 4x²)
(3 + 2x)(9 - 6x + 4x²)
(3 - 2x)(9 - 6x + 4x²)