Mathematics
a2 + b2 - c2 - d2 + 2ab - 2cd
Factorisation
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Answer
Given,
a2 + b2 - c2 - d2 + 2ab - 2cd
= a2 + b2 + 2ab - c2 - d2 - 2cd
= (a + b)2 - (c2 + d2 + 2cd)
= (a + b)2 - (c + d)2
= (a + b + c + d)(a + b - c - d).
Hence, a2 + b2 - c2 - d2 + 2ab - 2cd = (a + b + c + d)(a + b - c - d).
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