At what temperature in degree centigrade will the volume of a gas, which is originally at 0°C, double itself, pressure remaining constant?

V₁ = Initial volume of the gas = V
T₁ = Initial temperature of the gas = 0°C = 273 K
V₂ = Final volume of the gas = 2V
T₂ = Final temperature of the gas = ?

By Charles' Law:

$\dfrac{\text{V}$1}{\text{T}1} = \dfrac{\text{V}2}{\text{T}2}

Substituting the values :

$\dfrac{\text{V}}{273} = \dfrac{2\text{V}}{\text{T}$2} \\[1em] \text{T}2 = 2\times 273 \\[1em] \text{T}_2 = 546 \text{ K}

∴ Final temperature in °C = 546 - 273 = 273°C