An auto-rikshaw fare starts at ₹25 and remains the same for the initial 2 km. Then it increases by ₹15 per km. For how many km will the fare be ₹130?
Polynomials
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An auto-rikshaw fare starts at ₹25 and remains the same for the initial 2 km. Then it increases by ₹15 per km. For how many km will the fare be ₹130?

KnowledgeBoat · Accepted Answer

Let x be the total distance travelled (in km) and F be the fare (in ₹). For the initial 2 km, the fare is ₹25. After 2 km, the fare increases by ₹15 for every additional km. So for x km (where x 2), the fare is: F = 25 + 15(x − 2) Given that the fare is ₹130, we have: 130 = 25 + 15(x − 2) ⇒ 15(x − 2) = 130 − 25 ⇒ 15(x − 2) = 105 ⇒ x − 2 = ⇒ x − 2 = 7 ⇒ x = 7 + 2 ⇒ x = 9 Hence, the fare will be ₹130 for a travel of 9 km.

Mathematics

An auto-rikshaw fare starts at ₹25 and remains the same for the initial 2 km. Then it increases by ₹15 per km. For how many km will the fare be ₹130?

Polynomials

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An auto-rikshaw fare starts at ₹25 and remains the same for the initial 2 km. Then it increases by ₹15 per km. For how many km will the fare be ₹130?

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