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Mathematics

On average, 80 patients get admitted into a nursing home in a day. The ages of the patients admitted and their number are as given below :

Age (in years)No. of patients
10 - 2013
20 - 3023
30 - 4025
40 - 5014
50 - 605

Find :

(i) The average age for which maximum cases occur.

(ii) The upper limit of modal class.

(iii) The mean of the given data.

Measures of Central Tendency

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Answer

(i) The average age for which maximum cases occur is the mode of the distribution.

The maximum frequency is 25, so the modal class is 30 - 40.

Here, l = 30, f1 = 25, f0 = 23, f2 = 14 and h = 10.

By formula,

Mode=l+f1f02f1f0f2×h=30+25232(25)2314×10=30+25037×10=30+213×10=30+2013=30+1.54=31.54.\text{Mode} = l + \dfrac{f1 - f0}{2f1 - f0 - f_2} \times h \\[1em] = 30 + \dfrac{25 - 23}{2(25) - 23 - 14} \times 10 \\[1em] = 30 + \dfrac{2}{50 - 37} \times 10 \\[1em] = 30 + \dfrac{2}{13} \times 10 \\[1em] = 30 + \dfrac{20}{13} = 30 + 1.54 = 31.54.

Hence, the average age for which maximum cases occur is 31.54 years (approx.).

(ii) The modal class is 30 - 40.

Hence, the upper limit of the modal class is 40.

(iii) Mean of the data :

Age (in years)Class-mark (x)No. of patients (f)fx
10 - 201513195
20 - 302523575
30 - 403525875
40 - 504514630
50 - 60555275
TotalΣf = 80Σfx = 2550

By formula,

Mean = ΣfxΣf=255080\dfrac{Σfx}{Σf} = \dfrac{2550}{80} = 31.875 ≈ 31.88.

Hence, the mean of the given data is 31.88 years (approx.).

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