If A = B = 45°, show that : sin (A - B) = sin A cos B - cos A sin B

Question

KnowledgeBoat · Accepted Answer

sin (A - B) = sin A cos B - cos A sin B L.H.S. = sin (A - B) = sin (45° - 45°) = sin 0° = 0 R.H.S. = sin A cos B - cos A sin B = sin 45° . cos 45° - cos 45°. sin 45° ∴ L.H.S. = R.H.S. Hence, sin (A - B) = sin A cos B - cos A sin B.

Mathematics

If A = B = 45°, show that :
sin (A - B) = sin A cos B - cos A sin B

Trigonometric Identities

Related Questions

If A = 30°, then prove that :
2 cos² A - 1 = 1 - 2 sin² A

If A = 30°, then prove that :
sin 3A = 3 sin A - 4 sin³ A

If A = B = 45°, show that :
cos (A + B) = cos A cos B - sin A sin B

If 2sin A - 1 = 0 and A is an acute angle, the measure of angle A is :
30°
45°
60°
90°

Mathematics

If A = B = 45°, show that :sin (A - B) = sin A cos B - cos A sin B

Trigonometric Identities

Related Questions

If A = 30°, then prove that :2 cos2 A - 1 = 1 - 2 sin2 A

If A = 30°, then prove that :sin 3A = 3 sin A - 4 sin3 A

If A = B = 45°, show that :cos (A + B) = cos A cos B - sin A sin B

If 2sin A - 1 = 0 and A is an acute angle, the measure of angle A is :30°45°60°90°

If A = B = 45°, show that :
sin (A - B) = sin A cos B - cos A sin B

If A = 30°, then prove that :
2 cos² A - 1 = 1 - 2 sin² A

If A = 30°, then prove that :
sin 3A = 3 sin A - 4 sin³ A

If A = B = 45°, show that :
cos (A + B) = cos A cos B - sin A sin B

If 2sin A - 1 = 0 and A is an acute angle, the measure of angle A is :
30°
45°
60°
90°