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Mathematics

If a, b, c, d are in continued proportion, prove that :

(b + c)(b + d) = (c + a)(c + d)

Ratio Proportion

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Answer

Given,

⇒ a, b, c, d are in continued proportion

∴ a : b = b : c = c : d

ab=bc=cd\dfrac{a}{b} = \dfrac{b}{c} = \dfrac{c}{d} = k (let)

⇒ c = dk, b = ck = (dk)k = dk2, a = bk = (dk2)k = dk3.

Substituting values of a, b and c in L.H.S. of equation (b + c)(b + d) = (c + a)(c + d), we get :

⇒ (b + c)(b + d)

⇒ (d k2 + d k)(d k2 + d)

⇒ d2(k2 + k)(k2 + 1)

⇒ d2k(k + 1)(k2 + 1).

Substituting values of a, b and c in R.H.S. of equation (b + c)(b + d) = (c + a)(c + d), we get :

⇒ (c + a)(c + d)

⇒ (dk + dk3)(dk + d)

⇒ d2(k + k3)(k + 1)

⇒ d2k(1 + k2)(k + 1).

Since, L.H.S. = R.H.S.

Hence, (b + c)(b + d) = (c + a)(c + d).

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