Mathematics
If a, b, c, d are in continued proportion, prove that :
(b + c)(b + d) = (c + a)(c + d)
Ratio Proportion
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Answer
Given,
⇒ a, b, c, d are in continued proportion
∴ a : b = b : c = c : d
= k (let)
⇒ c = dk, b = ck = (dk)k = dk2, a = bk = (dk2)k = dk3.
Substituting values of a, b and c in L.H.S. of equation (b + c)(b + d) = (c + a)(c + d), we get :
⇒ (b + c)(b + d)
⇒ (d k2 + d k)(d k2 + d)
⇒ d2(k2 + k)(k2 + 1)
⇒ d2k(k + 1)(k2 + 1).
Substituting values of a, b and c in R.H.S. of equation (b + c)(b + d) = (c + a)(c + d), we get :
⇒ (c + a)(c + d)
⇒ (dk + dk3)(dk + d)
⇒ d2(k + k3)(k + 1)
⇒ d2k(1 + k2)(k + 1).
Since, L.H.S. = R.H.S.
Hence, (b + c)(b + d) = (c + a)(c + d).
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