The bisectors of ∠A and ∠B of the parallelogram ABCD intersect at E. ∠AEB =

1. 100°

2. 90°

3. 80°

4. 60°

In a parallelogram, consecutive angles are supplementary.

∠A + ∠B = 180°

In triangle AEB,

∠AEB + ∠BAE + ∠EBA = 180°

∠AEB + $\dfrac{1}{2}$ ∠A + $\dfrac{1}{2}$ ∠B = 180°

∠AEB + $\dfrac{1}{2}$ (∠A + ∠B) = 180°

∠AEB + $\dfrac{1}{2} \times$ (180°) = 180°

∠AEB + 90° = 180°

∠AEB = 180° - 90°

∠AEB = 90°.

Hence, option 2 is the correct option.