Physics
A body of mass 5 kg moves along a straight line under the action of a variable force. From x = 0 to x = 4 m, the force acts in the direction of displacement and increases linearly from 0 N to 20 N. From x = 4 m to x = 6 m, the motion of the body reverses while the force acts in forward direction. From x = 6 m to x = 10 m, the force becomes negative acting opposite to the original direction of motion. Calculate the net work done by the force on the body.
Related Questions
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(a) Compare: (i) the work done, (ii) the power developed by them.
(b) Calculate the (i) the work done, (ii) the power developed by each man.
Take g = 10N kg-1.
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(b) How much work each does?
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- displacement
- velocity
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- rotational kinetic energy
- translation kinetic energy
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