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Mathematics

A box containing cards numbered between 0 and 100 are shuffled and a card is picked at random. Find the probability of getting a card which is:

(a) divisible by 6.

(b) not divisible by 6.

Probability

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Answer

The cards are numbered from 0 to 100.

Total number of cards = 101 (as there is no. zero card also)

(a) Favorable outcome = Getting a card having a number which is divisible by 6.

{0, 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96}

Probability =No of favorable outcomesTotal number of outcomes=17101=\dfrac{\text{No of favorable outcomes}}{\text{Total number of outcomes}} = \dfrac{17}{101}.

Hence, probability of getting a card which is divisible by 6 = 17101\dfrac{17}{101}.

(b) Favorable outcome = Getting a card having a number which is not divisible by 6.

P(getting a card not divisible by 6) = 1 - P(getting a card divisible by 6)

= 1171011 - \dfrac{17}{101}

= 10117101\dfrac{101 - 17}{101}

= 84101\dfrac{84}{101}.

Hence, probability of getting a card which is not divisible by 6 = 84101\dfrac{84}{101}.

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