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The breakdown of glucose has taken the following pathway :

Glucose(a)Pyruvate+Energy(b)Lactic acid+Energy\text {Glucose} \xrightarrow {\text {(a)}} \text {Pyruvate} + \text {Energy} \xrightarrow {\text {(b)}} \text {Lactic acid} + \text {Energy}

The sites ‘a’ and ‘b’ respectively are :

options

  1. Mitochondria and Oxygen deficient muscle cells
  2. Cytoplasm and Oxygen rich muscle cells
  3. Cytoplasm and Yeast cells
  4. Cytoplasm and Oxygen deficient muscle cells

Respiratory System

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Answer

Cytoplasm and Oxygen deficient muscle cells

Reason — Glycolysis (Glucose → Pyruvate + energy) takes place in the cytoplasm of the cell and when oxygen is scarce, pyruvate is converted to lactic acid in oxygen-deficient (anaerobic) muscle cells, releasing a small amount of energy.

Hence the sites for (a) and (b) are cytoplasm and oxygen-deficient muscle cells respectively.

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